^{}

To find the area of a circle you would use the formula :

A =πr

^{2 }

^{}

^{ A is the area r is the radius of the circle WIth the given information you plug in the number(s) to the formula. }

^{ }

To find the area of a circle you would use the formula :

A =πr

To calculate the area of a regular polygon you would use the formula :

A = ½ * nas OR A= ½ * Pa

A is the area

P is the perimeter

a is the apothem

s is the length of each side

n is the number of sides

A = ½ * nas OR A= ½ * Pa

A is the area

P is the perimeter

a is the apothem

s is the length of each side

n is the number of sides

When solving the area to a figure like parallelograms, kites,and trapezoids, each one of those shapes has their own formula.

__Area of a Parallelogram:__

__Area of a Kite: __

__Area of a Trapezoid:__

_{ } Area= ½ ( 8 x 6)

_{} Area = ½ 5(10 + 14)

Example #1

Parallelogram Area = B x H

Area = 12 x 5

Area = 60 cm ²

Example #2

Kite Area = ½ d_{1}d_{2}

Area= ½ (48)

Area = 24 cm ²

Example #3

Trapezoid Area = ½ h( b_{1 +}b_{2} )

Area = ½ (120)

Area = 60in²

Area- The total amount of units inside of a figure / shape.

When trying to solve the area of a triangle and a rectangle theres a formula to each shape.

__Formula of a Triangle:__

__Formula of a Rectangle:__
__Example #1:__

A= ½b × h

A=½ (5) × (8)

A= ½ × 40

A= 20 in²

__ Example #2: __

Find the area of a rectangle with a base of 2cm. and height of 9cm.

A= b × h

A= (2)×(9)

A= 18 cm²

When trying to solve the area of a triangle and a rectangle theres a formula to each shape.

Find the area of a triangle with base of 5in. and the height of 8in.

A= ½b × h

A=½ (5) × (8)

A= ½ × 40

A= 20 in²

Find the area of a rectangle with a base of 2cm. and height of 9cm.

A= b × h

A= (2)×(9)

A= 18 cm²

When solving a compound locus problem, always involves two or more locus conditions in the same problem.

To know that there are more that one locus condition you would be able to identify it by seeing each one seperated by the words " AND " or " AND ALSO"

To solve the two or more, locus conditions in the same problem you have to solve each one seperately but on the same graph diagram.

To know that there are more that one locus condition you would be able to identify it by seeing each one seperated by the words " AND " or " AND ALSO"

To solve the two or more, locus conditions in the same problem you have to solve each one seperately but on the same graph diagram.

- A locus is a general graph of a given equation
- The locus is the set of all points that makes all the other points the same to the given condition
- There are 5 different locus

1. The locus of points equidistant ( the equal distance from another point)

from a

- Using the origin and forming a circle at the same distant all around the center( origin)

- Forming a line through the middle of the two points

- Two parallel lines would be equidistant formed on opposite side from the original line

4. Locus of points equidistant from

- a line would be through the middle of the two lines.

5. The locus of points from

- two intersecting lines halfway between the two original lines.

When making a conditional there is a rule we have to remember

which is ,

***If** hypotenuse **then** conclusion

**Example: **

** * **If the light is red, then the car will stop

* If it is not raining, then i will take my umbrella

When sovling the conditional to a inverse you have to,

* if*not* hypotenuse then __not__ conclusion.

**Example: **

* conditional- if i walk all day then i am tired

* inverse- if i do not walk all day then i am not tired

Solving a conditional to a converse,

*switch the hypotenuse and the conclusion.

**Example:**

*** **conditional - if i walk all day then i am tired

* inverse- if i am tired then i walk all day

Solving a conditional to a contrapositive (logical equivalent) follow this rule,

* if*not* **conclusion** then *not Hypotenuse*

**Example: **

** * **concditional- if i walk all day then i am tired

* contrapositive- if i am not tired, then i did not walk all day

which is ,

*

* If it is not raining, then i will take my umbrella

When sovling the conditional to a inverse you have to,

* if

* conditional- if i walk all day then i am tired

* inverse- if i do not walk all day then i am not tired

Solving a conditional to a converse,

*switch the hypotenuse and the conclusion.

* inverse- if i am tired then i walk all day

Solving a conditional to a contrapositive (logical equivalent) follow this rule,

* if

* contrapositive- if i am not tired, then i did not walk all day

what is a mathematical statement?

A mathematical statement is a statement that can be proven true or false.

This probably a everyday thing.

An example of a mathematical statement would be;

The principle of CPEHS is Mr. Lieberman and a teacher in CPEHS is Mr. Schnatterly.

** THE WORD AND SHOWS THAT THIS STATEMENT MUST BE TRUE FOR THE STATEMENT TO BE TRUE.

There are 4 different statements that can be formed ;

- the conditional

- inverse

- converse

- contrapositive or logical equivalent

The conditional;

If I use a pink pen, then I am lucky.

The inverse;

If I am not using a pink pen, then I am not lucky, .

The converse ;

If I am lucky, then I am using a pink pen.

The comtrapositive;

If I am not lucky, then I am not using a pink pen.

A mathematical statement is a statement that can be proven true or false.

This probably a everyday thing.

An example of a mathematical statement would be;

The principle of CPEHS is Mr. Lieberman and a teacher in CPEHS is Mr. Schnatterly.

** THE WORD AND SHOWS THAT THIS STATEMENT MUST BE TRUE FOR THE STATEMENT TO BE TRUE.

There are 4 different statements that can be formed ;

- the conditional

- inverse

- converse

- contrapositive or logical equivalent

The conditional;

If I use a pink pen, then I am lucky.

The inverse;

If I am not using a pink pen, then I am not lucky, .

The converse ;

If I am lucky, then I am using a pink pen.

The comtrapositive;

If I am not lucky, then I am not using a pink pen.

Subscribe to:
Posts (Atom)